x^2+1x+42=0

Solution for x^2+1x+42=0 equation:

Simplifying
x2 + 1x + 42 = 0

Reorder the terms:
42 + 1x + x2 = 0

Solving
42 + 1x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-42' to each side of the equation.
42 + 1x + -42 + x2 = 0 + -42

Reorder the terms:
42 + -42 + 1x + x2 = 0 + -42

Combine like terms: 42 + -42 = 0
0 + 1x + x2 = 0 + -42
1x + x2 = 0 + -42

Combine like terms: 0 + -42 = -42
1x + x2 = -42

The x term is 1x.  Take half its coefficient (0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
x + 0.25 + x2 = -42 + 0.25

Reorder the terms:
0.25 + x + x2 = -42 + 0.25

Combine like terms: -42 + 0.25 = -41.75
0.25 + x + x2 = -41.75

Factor a perfect square on the left side:
(x + 0.5)(x + 0.5) = -41.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.